| 2F-3 : | Determination of Pressure Inside a Tank Containing Ammonia | 5 pts | ||||||||||
| Ammonia is contained in a tank with a volume of 145 L. Determine the pressure when 25 kg of ammonia are in the tank and the temperature of the ammonia is 150oC. | ||||||||||||
| Data : | Tc | 405.4 |
K | ω | 0.250 |
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| Pc | 1.13E+07 |
Pa | MW | 17.01 |
g NH3 / mol NH3 | |||||||
| Read : | Not much to say here. | |||||||||||
| Given : | m | 25 |
kg | V | 145 |
L | ||||||
| T | 150 |
oC | 0.145 |
m3 | ||||||||
423.15 |
K | R | 8.314 |
J/mol-K | ||||||||
| Assumptions : | - The ammonia can accurately be treated as an ideal gas is this system. | |||||||||||
| Ideal Gas EOS : | Eqn 1 | Solve for pressure : | Eqn 2 | |||||||||
| We must determine the molar volume before we can use Eqn 2 to answer the question. | ||||||||||||
| Use the definition of molar volume: | Eqn 3 | Where : | Eqn 4 | |||||||||
| n | 1469.72 |
mol NH3 | V | 9.87E-05 |
m3/mol | |||||||
0.0987 |
L/mol | |||||||||||
| Now, plug values back into Eqn 2. | ||||||||||||
| Be careful with the units. | P | 3.57E+07 |
Pa | |||||||||
| P | 35.7 |
MPa | ||||||||||
| However, since the molar volume is less than 20 L/mole, the Ideal Gas EOS is not applicable. | ||||||||||||
| Choose any one of the following more sophisticated EOS's to solve the problem. | ||||||||||||
| Truncated Virial EOS : | ![]() |
Eqn 5 | ||||||||||
| We can estimate B using : | Eqn 6 | |||||||||||
| Eqn 7 | Eqn 8 | |||||||||||
| Where : | Eqn 9 | |||||||||||
| We can solve Eqn 5 for P : | Eqn 10 | |||||||||||
| Plugging numbers into Eqns 9, 7, 8, 6, 5 and 10 (in that order) yields : | ||||||||||||
| TR | 1.044 | B | -9.29E-05 |
m3/mol | ||||||||
| B0 | -0.3110 | Z | 5.89E-02 |
|||||||||
| B1 | -0.0047 | P | 2.1 |
MPa | ||||||||
| van der Waal EOS : | Eqn 11 | |||||||||||
| We can determine the values of a and b, which are constants that depend only on the chemical species in the system, from the following equations. | ||||||||||||
![]() |
Eqn 12 | Eqn 13 | ||||||||||
| a | 0.4229 |
Pa-mol2/m6 | b | 3.72E-05 |
m3/mol | |||||||
| Now, we can plug the constants a and b into Eqn 11 to determine the pressure. | ||||||||||||
| P | 13.8 |
MPa | ||||||||||
| Redlich-Kwong EOS : | ![]() |
Eqn 14 | ||||||||||
| We can determine the values of a, b and α, which are constants that depend only on the chemical species in the system, from the following equations. | ||||||||||||
![]() |
Eqn 15 |
Eqn 16 | ||||||||||
| Now, plug values into Eqns 14 -16 : | ||||||||||||
| a | 8.62780 |
Pa-m6-K1/2/mol2 | ||||||||||
| b | 2.577E-05 |
m3/mol | P | 14.1 |
MPa | |||||||
| Compressibility EOS : | Given TR and the ideal reduced molar volume, use the compressibility charts to evaluate either PR or the compressibility, Z | |||||||||||
|
Eqn 17 | Eqn 9 | ||||||||||
| TR | 1.0438 | |||||||||||
| Defiition of the ideal reduced molar volume : | ![]() |
Eqn 18 | ||||||||||
| VRideal | 0.3317 |
|||||||||||
| Read the Generalized Compressibility Chart for PR = 0 to 1 : | PR |
1.25 |
||||||||||
Z |
0.40 |
|||||||||||
| We can use the definition of PR to calculate P : | ||||||||||||
| Eqn 19 | ![]() |
Eqn 20 |
P | 14.2 |
MPa | |||||||
| Or, we can use Z and its definition to determine P : | ![]() |
Eqn 21 | ||||||||||
| P | 14.3 |
MPa | ||||||||||
| The Ammonia Tables provide the best available estimate of the pressure in the tank. | ||||||||||||
| Because T > Tc, the properties of the ammonia in the tank must be obtained from the superheated vapor table, even though the it is actually a supercritical fluid in this system. | ||||||||||||
| At this point we can make use of the fact that we have a pretty good idea of what the actual pressure is in the tank (from parts a-d) or we can scan the spuerheated vapor tables to determine which two pressures bracket our known value of the specific volume. | ||||||||||||
| In either case, we begin by converting the molar volume into a specific volume : | Eqn 22 | |||||||||||
| Using the MW of ammonia from part a yields : | v | 5.80E-06 |
m3/g | |||||||||
| v | 5.80E-03 |
m3/kg | ||||||||||
| The Superheated Ammonia Table gives us : | ||||||||||||
| At P = | 14 |
MPa | and | At P = | 16 |
MPa | ||||||
| v = | 0.0058196 |
m3/kg | v = | 0.0035504 |
m3/kg | |||||||
| We can determine the pressure in our tank by interpolation : | P | 14.0 |
MPa | |||||||||
| Verify: | The ideal gas assumption made in the beginning of this problem solution was not valid ! | |||||||||||
| Answers : | P | 14.0 |
MPa | |||||||||







