| 1B-2: | Mass, Force and Acceleration | 4 pts | |||||
| A 5 kg rock is thrown upward with a force of 150 N at a location where the local gravitational acceleration is 9.79 m/s2. Determine the acceleration of the rock in m/s2. | |||||||
| Read : | The key here is to recognize that two forces are acting on the rock: the 150 N and the weight of the rock (due to gravity). Then, the problem becomes an application of Newton's 1st Law of Motion. | ||||||
| Given : | m | 5 | kg | ||||
| Fthrow | 150 | N | |||||
| g | 9.79 | m/s2 | |||||
| Find : | a | ??? | m/s2 | ||||
| Solution : | The key equation here is Newton's 1st Law of Motion : | ||||||
| Eqn 1 | |||||||
| We can solve Eqn 1 for the rate at which the rock accelerates : | |||||||
| Eqn 2 | |||||||
| We know that : | gC | 1 | kg-m/N-s2 | ||||
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| So, all we need to is determine the net force acting on the stone. | |||||||
| A free-body diagram might be helpful. | |||||||
| The net force acting on the rock in the upward direction is : | |||||||
| Eqn 3 | |||||||
| We can apply Newton's 1st Law of Motion again to evaluate Fwt. |
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| Eqn 4 | |||||||
| We can solve Eqn 4 for Fwt, as follows : | Eqn 5 | ||||||
| Plugging values into Eqn 5, then Eqn 3 and, finally, Eqn 2 yields : | |||||||
| Fwt | 49.0 | N | |||||
| Fnet | 101.05 | N | |||||
| a | 20.21 | m/s2 | |||||
| Answers : | a | 20.2 | m/s2 | ||||
