Entropy Change for a Reversible, Isothermal Process
In general, it is not possible to evaluate ΔS directly by integrating dQ/T.
However, in the special case of an
isothermalprocess it is possible and easy too!
Because temperature is constant, T can be pulled out of the intergral:
Internally Reversible, Isothermal Processes
This is particularly useful for determining the change in entropy of a
thermal reservoiror for the two reversible, isothermal steps in the
T1 = T2
T1 = T2
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